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Integral of 1/(x^2+2x+2) (substitution) [新しいコレクション] x 3/x-3 x 2/x-2=2 228406-x^3+x-(x-2)(x^2+2x+4) Solved integrate: integral 3x^2 + 3x + 3/x^2 + 1 dx

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